document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=466337>Question 466337</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 8. A comittee of 10 women and 9 men is looking to create a 6 person committee. <BR>\n" );
document.write( "     a. how many ways are there of choosing this committee?<BR>\n" );
document.write( "           19*18*17*16*15*14=19535040<BR>\n" );
document.write( "     b. How many ways are there of chosing 4 men and 2 women?<BR>\n" );
document.write( "              (i'm confused)<BR>\n" );
document.write( "     c. Whats the probability that it's selected with 4 men and 2 women?<BR>\n" );
document.write( "              (I havent a clue)<BR>\n" );
document.write( "     d. What is the probility that it's selected with 5 women and 1 man?<BR>\n" );
document.write( "              ( i do not know)\r<BR>\n" );
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document.write( "Please help! Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #319668 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=319668\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a: Order doesn't matter, so it is 19C6 = (19*18*...*14)/6!\r<BR>\n" );
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document.write( "b: Choose the men separately, and the women separately. Hence there are 9C4*10C2 ways.\r<BR>\n" );
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document.write( "c: The probability is simply the answer to b) over the answer to a), assuming all combinations are equally likely.\r<BR>\n" );
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document.write( "d: We do d) the same way as we did b). There are 10C5*9C1 ways to select such a committee. Divide this by the total number to obtain the probability. </SPAN>\n" );
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