document.write( "Question 48335: Hi, I have this problem to solve, and would really appreciate some help: |5-2x|>3
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Algebra.Com's Answer #31963 by tutorcecilia(2152)\"\" \"About 
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|5-2x|>3 [There are two conditions that must be considered in problems with absolute values: either x > 0 or x < 0]
\n" ); document.write( "|5-2x|>3 [First condition where x>+3]
\n" ); document.write( "5-2x>3 [Solve for x]
\n" ); document.write( "-5 + 5-2x>3-5
\n" ); document.write( "-2x>-2
\n" ); document.write( "-2x/-2<-2/-2 [Switch the sign when multiplying or dividing by a negative number]
\n" ); document.write( "x<1\r
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\n" ); document.write( "|5-2x|>3 [Second condition where x<-3]
\n" ); document.write( "5-2x<-3
\n" ); document.write( "5-2x<-3 [Solve for x]
\n" ); document.write( "-5+5-2x<-3-5
\n" ); document.write( "-2x<-8
\n" ); document.write( "-2x/-2>-8/-2 [Switch the sign when multiplying or dividing by a negative number]
\n" ); document.write( "x>4\r
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\n" ); document.write( "So, x<1 or x>4\r
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