document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=466278>Question 466278</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Person A is 35, person B is 10. How old will both person A, and B be when person A is 3 times older than person B?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #319628 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=319628\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Person A is 35, person B is 10. How old will both person A, and B be when person A is 3 times older than person B?<BR>\n" );
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document.write( "A = B + 25<BR>\n" );
document.write( "A + x = 4(B + x) in x years<BR>\n" );
document.write( "B + 25 + x = 4B + 4x<BR>\n" );
document.write( "10 + 25 + x = 4*10 + 4x<BR>\n" );
document.write( "35 + x = 40 + 4x<BR>\n" );
document.write( "-5 = 3x<BR>\n" );
document.write( "x = -5/3 years<BR>\n" );
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document.write( "When A is 100/3 years and B is 25/3 years of age.<BR>\n" );
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document.write( "3 times older is 4 times as old. </SPAN>\n" );
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