document.write( "Question 466268: Find the equations of both the horizontal and vertical asymptotes of the rational function \r
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document.write( "f(x)= 2x^2+8/x-1
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document.write( "Answer:
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document.write( "Horizontal:
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document.write( "Vertical:
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document.write( "Show work or explain: \n" );
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Algebra.Com's Answer #319599 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Find the equations of both the horizontal and vertical asymptotes of the rational function \n" ); document.write( "f(x)= 2x^2+8/x-1 \n" ); document.write( "Answer: \n" ); document.write( "Horizontal: \n" ); document.write( "Vertical: \n" ); document.write( "Show work or explain: \n" ); document.write( ".. \n" ); document.write( "f(x)= 2x^2+8/x-1 \n" ); document.write( "To find the vertical asymptote, set the denominator=0, then solve for x. \n" ); document.write( "x-1=0 \n" ); document.write( "x=1 (vertical asymptote) \n" ); document.write( ".. \n" ); document.write( "horizontal asymptote: \n" ); document.write( "When degree of numerator is less than degree of denominator, horizontal asymptote=x-axis or y=0. \n" ); document.write( "When degree of numerator is equal to degree of denominator, divide coefficient of numerator by coefficient of denominator to get the horizontal asymptote. \n" ); document.write( "When degree of numerator is one degree greater than that of denominator, you will get a slant asymptote, which is the case for given rational function. To find the slant asymptote, divide numerator by denominator. The quotient will be a straight-line function plus remainder. The straight-line function will be the slant asymptote. \n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "2x^2+8/x-1 \n" ); document.write( "=2x+2+Remainder:(10/x-1) \n" ); document.write( "slant asymptote, y=2x+2 \n" ); document.write( " |