document.write( "Question 45161: Jill has $3.50 in nickels and dimes.If she has 50 coins, how many of each type of coin does she have? \n" ); document.write( "
Algebra.Com's Answer #31957 by maribeth_abella(11) ![]() You can put this solution on YOUR website! lets say the the nickels is n while the dimes is d.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "first equation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n + d = the number of coins\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n + d = 50\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "second equation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "amount of a nickel ( n ) + amount of a dime ( d ) = the total amount\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0.05 ( n ) + 0.10 ( d ) = $3.50\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply to both side by 100 beacause we need to make the dollar to cent so if \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you convert $1=100 cents.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "100 [ 0.05 ( n ) + 0.10 ( d ) = $3.50 ] 100\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5 ( n ) + 10 ( d ) = 350\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5n + 10d = 350\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so the second equation is 5n + 10d = 350\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, we solve the two equations to get the no. of dimes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " n + d = 50\r \n" ); document.write( "\n" ); document.write( "5n + 10d = 350\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then, we multiply the first equation by -5. The result would be like this:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-5n - 5d = -250 \n" ); document.write( " 5n + 10d = 350\r \n" ); document.write( "\n" ); document.write( "5d = 100\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "then, divide both side by the numerical co-efficient 5 .\r \n" ); document.write( "\n" ); document.write( "d = 20\r \n" ); document.write( "\n" ); document.write( "so, the number of dimes is 20.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "now, the no. of nickels: \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "now, we have to substitute d to 20 and use equation 1(but you can use \r \n" ); document.write( "\n" ); document.write( "equation 2 if you like) because we can get the number of nickels.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n + 20 = 50\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "then, transpose 20 to the other side.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n = 30\r \n" ); document.write( "\n" ); document.write( "so, the no. of nickels is 30.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "THEN, WE CAN CONCLUDE THAT THE NO> OF DIMES IS 20 AND THE NICKEL IS 30.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |