document.write( "Question 466239: Automotive maintenance. The radiator in Natalie’s car contains 6.3 L of antifreeze and water. This mixture is 30% antifreeze. How much of this mixture should she drain and replace with pure antifreeze so that there will be a mixture of 50% antifreeze.\r
\n" ); document.write( "\n" ); document.write( "(6.3 - x)(30%) + (x)(100%) = (6.3)(50%)
\n" ); document.write( "So what 6.3L should be drained? Im not sure where to go with this. \n" ); document.write( "
Algebra.Com's Answer #319560 by stanbon(75887)\"\" \"About 
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Automotive maintenance. The radiator in Natalie’s car contains 6.3 L of antifreeze and water. This mixture is 30% antifreeze. How much of this mixture should she drain and replace with pure antifreeze so that there will be a mixture of 50% antifreeze.
\n" ); document.write( "---
\n" ); document.write( "alcohol -alcohol + alcohol = alcohol
\n" ); document.write( "0.30*6.3 -0.30x + 1.00x = 0.50*6.3
\n" ); document.write( "--------------------------------
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "30*6.3 - 30x + 100x = 50*6.3
\n" ); document.write( "------
\n" ); document.write( "70x = 20*6.3
\n" ); document.write( "x = (2/7)6.3
\n" ); document.write( "---
\n" ); document.write( "x = 2*0.9
\n" ); document.write( "x = 1.8 Liters (amt. of mixture that should be removed and replaced).
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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