document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=466234>Question 466234</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm kinda confused about how to solve this problem. Do i just solve the denominator or what. Set x=4, the problem is 4x/x^3-2. Can you please help me tonight.  Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #319553 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=319553\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4x<BR>\n" );
document.write( "------<BR>\n" );
document.write( "x³ - 2\r<BR>\n" );
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document.write( "4(4)<BR>\n" );
document.write( "------ {substituted 4 in for x}<BR>\n" );
document.write( "4³ - 2\r<BR>\n" );
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document.write( "16<BR>\n" );
document.write( "------- {took 4 to the third power}<BR>\n" );
document.write( "64 - 2\r<BR>\n" );
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document.write( "16<BR>\n" );
document.write( "--- {subtracted 64 - 2}<BR>\n" );
document.write( "62\r<BR>\n" );
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document.write( "= 8/31 {reduced}<BR>\n" );
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