document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=466173>Question 466173</A>: <I><SPAN STYLE=\"word-break: break-all;\"> given one side of a 30-60-90 triangle how do you find the other 2 sides? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #319541 by </B><A HREF=/tutors/aboutme.mpl?userid=Gogonati><B>Gogonati(855)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Gogonati><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Gogonati><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=319541\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We'll describe three cases:<BR>\n" );
document.write( "1)The given side is the hypotenuse, equal a: Then the leg opposite to the 30 degree angle is a/2 and the other leg base on the Pythagorean theorem will be:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28a%5E2-%28a%2F2%29%5E2%29=sqrt%28a%5E2-a%5E2%2F4%29=sqrt%283a%5E2%2F4%29=a%2Asqrt%283%29%2F2 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "2)The given side is the side opposite to the 30 degree angle, equal b: Then the <BR>\n" );
document.write( "hypotenuse will be 2b, and the other leg base on the Pythagorean theorem will be\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28%282b%29%5E2-b%5E2%29=sqrt%283b%5E2%29=b%2Asqrt%283%29 ALIGN=MIDDLE  ALT=\"sqrt%28%282b%29%5E2-b%5E2%29=sqrt%283b%5E2%29=b%2Asqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "3)The given side is the side opposite to the angle 60 degree, equal c: <BR>\n" );
document.write( "Assume that the angle opposite to the angle 30 degree is x, then the hypotenuse is 2x, and using the Pythagorean theorem we write:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c%5E2=%282x%29%5E2-x%5E2 ALIGN=MIDDLE  ALT=\"c%5E2=%282x%29%5E2-x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><=><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c%5E2=3x%5E2 ALIGN=MIDDLE  ALT=\"c%5E2=3x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><=><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=sqrt%28c%5E2%2F3%29=c%2Asqrt%283%29%2F3 ALIGN=MIDDLE  ALT=\"x=sqrt%28c%5E2%2F3%29=c%2Asqrt%283%29%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and the hypotenuse will be: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2c%2Asqrt%283%29%2F3 ALIGN=MIDDLE  ALT=\"2c%2Asqrt%283%29%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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