document.write( "Question 466195: graph the function f by starting with the graph of y = x2 and using transformations (shifting, compressing, stretching, and/or reflection). \r
\n" ); document.write( "\n" ); document.write( "[Hint: If necessary, write f in the form f(x) = a(x – h)2 + k.]\r
\n" ); document.write( "\n" ); document.write( "f(x) = –2x2 + 6x + 2
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Algebra.Com's Answer #319526 by lwsshak3(11628)\"\" \"About 
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graph the function f by starting with the graph of y = x2 and using transformations (shifting, compressing, stretching, and/or reflection).
\n" ); document.write( "[Hint: If necessary, write f in the form f(x) = a(x – h)2 + k.]
\n" ); document.write( "f(x) = –2x2 + 6x + 2
\n" ); document.write( "..
\n" ); document.write( " –2x^2 + 6x + 2
\n" ); document.write( "completing the square
\n" ); document.write( "-2(x^2-3x+9/4)+2+9/2
\n" ); document.write( "-2(x-3/2)^2+13/2
\n" ); document.write( "This is a parabola of the standard form, y=A(x-h)^2+k, with h=3/2 and k=13/2, and it opens downward.
\n" ); document.write( "see the graph of this parabola as follows:
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\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C-2%28x-3%2F2%29%5E2%2B13%2F2%29+\"
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\n" ); document.write( "The next graph shows the result of removing the coefficient A=2. Notice how the curve is a little wider or less steep. The larger this coefficient, the steeper the curve.
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\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+-%28x-3%2F2%29%5E2%2B13%2F2%29+\"\r
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\n" ); document.write( "The next graph shows the result of removing (h,k) the (x,y) coordinates of the vertex.
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\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+-x%5E2%29+\"
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\n" ); document.write( "Removing the negative coefficient
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\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+x%5E2%29+\"
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