document.write( "Question 466060: The height of an object thrown upward from the floor of a canyon 106 ft. deep, with an initial velocity of 120 ft/sec is given by the equation:
\n" ); document.write( "h=-16t2 + 120t-106 How long will it take the object to rise to the height of the canyon wall? Round answer to the nearest hundreth.
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Algebra.Com's Answer #319484 by ankor@dixie-net.com(22740)\"\" \"About 
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The height of an object thrown upward from the floor of a canyon 106 ft. deep,
\n" ); document.write( " with an initial velocity of 120 ft/sec is given by the equation:
\n" ); document.write( "h=-16t2 + 120t-106 How long will it take the object to rise to the height of the canyon wall?
\n" ); document.write( " Round answer to the nearest hundreth.
\n" ); document.write( ":
\n" ); document.write( "Height of the canyon wall = 0, depth of the canyon -106, so we have
\n" ); document.write( "-16t^2 + 120t - 106 = 0
\n" ); document.write( "Use the quadratic formula:
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "In this equation: t=x, a=-16, b-120, c=-106
\n" ); document.write( "\"t+=+%28-120+%2B-+sqrt%28120%5E2-4%2A-16%2A-106+%29%29%2F%282%2A-16%29+\"
\n" ); document.write( ":
\n" ); document.write( "\"t+=+%28-120+%2B-+sqrt%2814400-6784+%29%29%2F%28-32%29+\"
\n" ); document.write( ":
\n" ); document.write( "\"t+=+%28-120+%2B-+sqrt%287616+%29%29%2F%28-32%29+\"
\n" ); document.write( "Two solutions
\n" ); document.write( "\"t+=+%28-120+%2B+87.27%29%2F%28-32%29+\"
\n" ); document.write( "t = \"%28-32.73%29%2F%28-32%29\"
\n" ); document.write( "t = 1.023 sec, this is the solution we want, time at the top of the wall on the way up
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