document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=466081>Question 466081</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many gallons of pure alcohol should be mixed with 20 gallons of a 15 % alcohol solution to obtain a 25% alcohol mixture? It should be two equations that can then be solved using substitution or elimination </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #319433 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=319433\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 20(.15)+m=.25(20+m)<BR>\n" );
document.write( "m+3=5+.25m<BR>\n" );
document.write( ".75m=2<BR>\n" );
document.write( "m=2/.75=2.67<BR>\n" );
document.write( "You need 2.67 gallons of pure alcohol to strengthen your mixture..<BR>\n" );
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