document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=466055>Question 466055</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3x + 2y = 2 -2x + y = 8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #319421 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=319421\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x + 2y = 2 -----> 3x + 2y = 2 {top equation stays the same}<BR>\n" );
document.write( "-2x + y = 8 -----> 4x - 2y = -16 {multiplied bottom equation by -2}\r<BR>\n" );
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document.write( "7x = -14 {added the two new equations together}<BR>\n" );
document.write( "x = -2 {divided both sides by 7}\r<BR>\n" );
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document.write( "3x + 2y = 2 {original top equation}<BR>\n" );
document.write( "3(-2) + 2y = 2 {substituted -2, in for x, into top equation}<BR>\n" );
document.write( "-6 + 2y = 2 {multiplied 3 by -2}<BR>\n" );
document.write( "2y = 8 {added 6 to both sides}<BR>\n" );
document.write( "y = 4 {divided both sides by 2}\r<BR>\n" );
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document.write( "x = -2 and y = 4<BR>\n" );
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