document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=466036>Question 466036</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the measure of an angle who supplement measures 39 more than twice its complement.\r<BR>\n" );
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document.write( "Like to know if I am setting up the equation properly?\r<BR>\n" );
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document.write( "Angle = x<BR>\n" );
document.write( "Supplement = 180-x<BR>\n" );
document.write( "Complement = 90-x\r<BR>\n" );
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document.write( "180-x = 2(90-x)+39<BR>\n" );
document.write( "180 = 219<BR>\n" );
document.write( "x= 39\r<BR>\n" );
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document.write( "Can I also say the supplement is 141 degrees and the complement is 56 degrees even though the problem is not requesting to find them?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #319402 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=319402\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the measure of an angle who supplement measures 39 more than twice its complement.<BR>\n" );
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document.write( "Angle = x<BR>\n" );
document.write( "Supplement = 180-x<BR>\n" );
document.write( "Complement = 90-x <BR>\n" );
document.write( "180-x = 2(90-x)+39<BR>\n" );
document.write( "----------  180 does not equal 219. I think you're subtracting there.<BR>\n" );
document.write( "180-x = 180 - 2x + 39<BR>\n" );
document.write( "-x = -2x + 39<BR>\n" );
document.write( "x = 39 degs<BR>\n" );
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document.write( "Supp = 141, comp = 51 </SPAN>\n" );
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