document.write( "Question 466036: Find the measure of an angle who supplement measures 39 more than twice its complement.\r
\n" ); document.write( "\n" ); document.write( "Like to know if I am setting up the equation properly?\r
\n" ); document.write( "\n" ); document.write( "Angle = x
\n" ); document.write( "Supplement = 180-x
\n" ); document.write( "Complement = 90-x\r
\n" ); document.write( "\n" ); document.write( "180-x = 2(90-x)+39
\n" ); document.write( "180 = 219
\n" ); document.write( "x= 39\r
\n" ); document.write( "\n" ); document.write( "Can I also say the supplement is 141 degrees and the complement is 56 degrees even though the problem is not requesting to find them?
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Algebra.Com's Answer #319400 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "Find measure of an angle who supplement measures 39 more than twice its complement
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document.write( "you set it up very nicely!
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document.write( "180-x = 2(90-x)+39
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document.write( "180 = 219
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document.write( "x = 39, angle requested\r
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document.write( "CHECKING our Answer*** Finding Supp = 141 and Comp = 51 works nicely for checking,
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document.write( "Question only requested the original angle x however.
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document.write( " 141 = 2*51 + 39 = 102 + 39 = 141 \n" );
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