document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=466036>Question 466036</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the measure of an angle who supplement measures 39 more than twice its complement.\r<BR>\n" );
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document.write( "Like to know if I am setting up the equation properly?\r<BR>\n" );
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document.write( "Angle = x<BR>\n" );
document.write( "Supplement = 180-x<BR>\n" );
document.write( "Complement = 90-x\r<BR>\n" );
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document.write( "180-x = 2(90-x)+39<BR>\n" );
document.write( "180 = 219<BR>\n" );
document.write( "x= 39\r<BR>\n" );
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document.write( "Can I also say the supplement is 141 degrees and the complement is 56 degrees even though the problem is not requesting to find them?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #319399 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=319399\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You are correct in setting up the equation, and your final answer is correct; you probably typoed when you wrote \"180 = 219\" when it should be \"180 = 219 - x.\" And the complement of 39 degrees is 90 - 39 = 51 degrees. You do not have to state the supplement or the complement for this problem. </SPAN>\n" );
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