document.write( "Question 464834: The perimeter of a rectangle is 34 inches, and the area is 60 square inches. What is the length and width of the rectangle. \n" ); document.write( "

Algebra.Com's Answer #319363 by sofiyac(983) $\"\"$ $\"About$

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let width be x and length y, then
\n" ); document.write( "2x+2y=34
\n" ); document.write( "xy=60
\n" ); document.write( "solve the system
\n" ); document.write( "x=60/y
\n" ); document.write( "2(60/y)+2y=34
\n" ); document.write( "120/y+2y=34
\n" ); document.write( "120+2y^2=34y
\n" ); document.write( " $\"2y%5E2-34y%2B120=0\"$
\n" ); document.write( " $\"y%5E2-17y%2B60=0\"$
\n" ); document.write( "(y-5)(y-12)=0
\n" ); document.write( "y=5 and y=12
\n" ); document.write( "so the sides are 5 and 12 since 5*12=60 \n" ); document.write( "

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