document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=465975>Question 465975</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two angles are supplementary. three times the measure of the smaller angle is five less than twice of the measure of the larger angle. find the measure of esch angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #319327 by </B><A HREF=/tutors/aboutme.mpl?userid=sofiyac><B>sofiyac(983)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sofiyac><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sofiyac><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=319327\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Supplementary angles add to 180 degrees.<BR>\n" );
document.write( "let smaller angle be x, then<BR>\n" );
document.write( "3x+5=2y<BR>\n" );
document.write( "x+y=180<BR>\n" );
document.write( "Multiply second equation by -3 then add it to the first one<BR>\n" );
document.write( "3x-2y=-5<BR>\n" );
document.write( "-3x-3y=-540  When you add them, the x's cancel out (because they add to zero)<BR>\n" );
document.write( "**********<BR>\n" );
document.write( "-5y=-545 divide each side by -5<BR>\n" );
document.write( "y=109<BR>\n" );
document.write( "if y is 109 then x would be <BR>\n" );
document.write( "x=180-109=71<BR>\n" );
document.write( "So the angles are 71 and 109 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );