document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=465899>Question 465899</A>: <I><SPAN STYLE=\"word-break: break-all;\"> JIM NEEDS TO PREPARE ONE LITER OF A 4% NACL SOLUTION. HOW MUCH NACL SHOULD HE WEIGH OUT? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #319306 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=319306\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4% of a 1 L NaCl solution is .04 L = 40 mL = 40 cm^3. However we want to find the mass of the salt by doing a unit conversion (had to look up the density online):\r<BR>\n" );
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document.write( "(40 cm^3)(2.165 g/cm^3) = 86.6 g </SPAN>\n" );
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