document.write( "Question 465936: Indicate the equation of the given line in standard form.\r
\n" ); document.write( "\n" ); document.write( "The line through the midpoint of and perpendicular to the segment joining points (1, 0) and (5, -2).
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Algebra.Com's Answer #319296 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
The slope of the line joining(1, 0) and (5, -2) is \"%28-2+-+0%29%2F%285+-+1%29+=+-2%2F4+=+-1%2F2\". the perpendicular slope is then the negative reciprocal, which is 2.\r
\n" ); document.write( "\n" ); document.write( "The midpoint between (1, 0) and (5, -2) is (3, - 1). \r
\n" ); document.write( "\n" ); document.write( "The equation of the line is then\r
\n" ); document.write( "\n" ); document.write( "y - -1 = 2(x - 3),
\n" ); document.write( "<==> y+1 = 2x - 6, or 2x - y = 7, or 2x - y - 7 = 0, whatever your fancy is.
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