document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=465918>Question 465918</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Just don't get it...<BR>\n" );
document.write( "Find the equation of the line with slope -7/2 and passes through (-2,5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #319276 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=319276\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Start with the slope-intercept form:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+mx+%2B+b ALIGN=MIDDLE  ALT=\"y+=+mx+%2B+b\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "In which m is the slope and b is the value on the y-axis where the graph crosses the y-axis. You are told that the slope is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-7%2F2 ALIGN=MIDDLE  ALT=\"-7%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >. This value can be substituted for m in the slope-intercept form to get:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+%28-7%2F2%29x+%2B+b ALIGN=MIDDLE  ALT=\"y+=+%28-7%2F2%29x+%2B+b\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "You are also told that the point (-2,5) is on the graph. All the points on the graph have to satisfy the slope-intercept form.  Therefore, when x is -2 and y is +5, they satisfy the slope-intercept equation.  So we can substitute -2 for x and +5 for y and know that the equation must be true. When we make those substitutions, the equation becomes:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5+=+%28-7%2F2%29%2A%28-2%29+%2B+b ALIGN=MIDDLE  ALT=\"5+=+%28-7%2F2%29%2A%28-2%29+%2B+b\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Do the multiplication of the first term on the right side of the equal sign to get:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5+=+7+%2B+b ALIGN=MIDDLE  ALT=\"5+=+7+%2B+b\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Solve for b by subtracting 7 from both sides to find that:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5+-+7+=+%2Bb ALIGN=MIDDLE  ALT=\"5+-+7+=+%2Bb\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "which simplifies to:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b+=+-2 ALIGN=MIDDLE  ALT=\"b+=+-2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "At this point we know that the slope is -7/2 and -2 is the value on the y-axis where the graph crosses. Therefore, substituting these two values (m and b) into the slope-intercept equation of a line results in the equation becoming:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+%28-7%2F2%29%2Ax+-2 ALIGN=MIDDLE  ALT=\"y+=+%28-7%2F2%29%2Ax+-2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "And this is the answer. It is an equation for the line having a slope of -7/2 and also having the point (-2,5) on the line.  <BR>\n" );
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document.write( "Hope this helps you to understand how to work with one of the forms of an equation that describes a specific straight line line on a graph. </SPAN>\n" );
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