document.write( "Question 465887: I am supposed to solve this:
\n" ); document.write( "3+ root symbol (z-8) = root symbol(z+7)\r
\n" ); document.write( "\n" ); document.write( "I am not sure what to do here, any help would be appreciated! With explanation if possible!
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Algebra.Com's Answer #319272 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Given:
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\n" ); document.write( "\"3%2Bsqrt%28z-8%29=+sqrt%28z%2B7%29\"
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\n" ); document.write( "The next step is to square both sides. Squaring the left side is done by multiplying:
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\n" ); document.write( "\"%283%2Bsqrt%28z-8%29%29%2A%283%2Bsqrt%28z-8%29%29\"
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\n" ); document.write( "This can be done by using the FOIL method ... multiply First Terms, then Outside Terms, then Inside Terms, and finally Last Terms. When you do that you get:
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\n" ); document.write( "\"%283%2A3%29%2B3%2Asqrt%28z-8%29+%2B3%2Asqrt%28z-8%29%2Bsqrt%28z-8%29%2Asqrt%28z-8%29\"
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\n" ); document.write( "This simplifies to:
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\n" ); document.write( "\"9+%2B+6%2Asqrt%28z-8%29%2B%28z-8%29\" which further simplifies to:
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\n" ); document.write( "\"9+%2B+6%2Asqrt%28z-8%29%2Bz+-8\"
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\n" ); document.write( "and the +9 and -8 combines to +1 so the expression reduces to:
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\n" ); document.write( "\"6%2Asqrt%28z-8%29+%2Bz+%2B+1\"
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\n" ); document.write( "Now return to square the right side of the equation as follows:
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\n" ); document.write( "\"sqrt%28z%2B7%29%2Asqrt%28z%2B7%29+=+z%2B7\"
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\n" ); document.write( "So after squaring both sides the equation becomes:
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\n" ); document.write( "\"6%2Asqrt%28z-8%29+%2B+z+%2B+1+=+z+%2B+7\"
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\n" ); document.write( "Subtract z from both sides reduces this to:
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\n" ); document.write( "\"6%2Asqrt%28z-8%29+%2B+1+=+7\"
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\n" ); document.write( "Next subtract 1 from both sides to get:
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\n" ); document.write( "\"6%2Asqrt%28z-8%29+=+6\"
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\n" ); document.write( "Divide both sides by 6:
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\n" ); document.write( "\"sqrt%28z-8%29+=+1\"
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\n" ); document.write( "Square both sides:
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\n" ); document.write( "\"z-8+=+1\"
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\n" ); document.write( "Finally add 8 to both sides and the result is:
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\n" ); document.write( "\"z+=+9\"
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\n" ); document.write( "That's the answer. You can check this by returning to the original equation, substituting 9 for z, and working it out to see that both sides are equal. In other words, start with:
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\n" ); document.write( "\"3%2Bsqrt%28z-8%29=+sqrt%28z%2B7%29\"
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\n" ); document.write( "Substitute 9 for z:
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\n" ); document.write( "\"3+%2B+sqrt%289-8%29=sqrt%289%2B7%29\"
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\n" ); document.write( "Combine the numbers under each radical to get:
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\n" ); document.write( "\"3+%2B+sqrt%281%29=sqrt%2816%29\"
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\n" ); document.write( "This reduces to:
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\n" ); document.write( "\"3+%2B+1+=+4\"
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\n" ); document.write( "And this is true (4 does equal 4) so our answer of z = 9 does satisfy the original equation.
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\n" ); document.write( "Hope this helps you to understand that squaring radicals is a way to solve problems such as these.
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