document.write( "Question 465841: Leslie invested $3000 at 6% per year. How much should she invest at 9% per year so that the annual income from the two investments is 8%. \n" ); document.write( "
Algebra.Com's Answer #319230 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! 3000(.06)+m(.09)=.08(3000+m) \n" ); document.write( "180+.09m=240+.08m \n" ); document.write( ".01m=60 \n" ); document.write( "m=60/.01=6000 \n" ); document.write( "Leslie needs $6000 at 9% a year to reach her goal.. \n" ); document.write( " |