document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=48250>Question 48250</A>: <I><SPAN STYLE=\"word-break: break-all;\"> add or subtract as indicated, express your results in simplest form<BR>\n" );
document.write( "5a-12/a^2-8a+15 - 3a-2/a^2-8a+15 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31919 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31919\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5a-12/a^2-8a+15 - 3a-2/a^2-8a+15 [Since the denominators are the same, subtract]<BR>\n" );
document.write( "(5a-12) - (3a - 2)/a^2-8a+15  [Combine like-terms]<BR>\n" );
document.write( "5a-12 - 3a + 2/a^2-8a+15<BR>\n" );
document.write( "2a-10/a^2-8a+15  [Factor wherever possible]<BR>\n" );
document.write( "2(a-5)/(a-5)(a-3)  [Cancel out wherever possible]<BR>\n" );
document.write( "2/a-3  [Final answer] </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );