document.write( "Question 465710: Given the function f(x) = -x²+2x+3
\n" ); document.write( "(A)Determine the vertex,
\n" ); document.write( "(B)List the axis of symmetry,
\n" ); document.write( "(C)calculate the y-intercept,
\n" ); document.write( "(D)find an additional point on the graph, and
\n" ); document.write( "(E)graph the function.
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\n" ); document.write( "\n" ); document.write( "I appreciate any help.
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Algebra.Com's Answer #319173 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi
\n" ); document.write( "y = -x^2+2x+3 | y-intercept Pt(0,3)
\n" ); document.write( "Using the vertex form of a parabola, \"y=a%28x-h%29%5E2+%2Bk\" where(h,k) is the vertex
\n" ); document.write( "y = -x^2+2x+3 |completing the square
\n" ); document.write( "y = -[(x-1)^2 -1]+3
\n" ); document.write( "y = -(x-1)^2 +4 Vertex (1,4) a = -1 <0 Parbola opens downward, vertex is max pt
\n" ); document.write( "Line of symmetry is x = 1 and when y = 0 (x-1)^2 = 4 x = 3
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