document.write( "Question 465528: How much 20% anti-freeze should be mixed with 60% anti-freeze to get 10 liters of 28% anti-freeze? \n" ); document.write( "

Algebra.Com's Answer #319152 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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How much 20% anti-freeze should be mixed with 60% anti-freeze to get 10 liters of 28% anti-freeze?
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\n" ); document.write( "Let x = amt of 60% stuff
\n" ); document.write( "then
\n" ); document.write( "(10-x) = amt of 20%
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\n" ); document.write( "Write a mixture equation using decimals
\n" ); document.write( ".60x + .20(10-x) = .28(10)
\n" ); document.write( ".60x + 2 - .20x = 2.8
\n" ); document.write( ".6x - .2x = 2.8 - 2
\n" ); document.write( ".4x = .8
\n" ); document.write( "x = $\".8%2F.4\"$
\n" ); document.write( "x = 2 liters of 60% stuff
\n" ); document.write( "then
\n" ); document.write( "10 - 2 = 8 liters of 20%
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\n" ); document.write( "Check this: .6(2) + .2(8) = .28(10)
\n" ); document.write( "1.2 + 1.6 = 2.8 \n" ); document.write( "

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