document.write( "Question 48241This question is from textbook College Algebra
\n" ); document.write( ": The burial cloth of an Egyptian mummy is estimated to contain 59% of the carbon-14 it contained originally. How long ago was the mummy buried? (The half-life of carbon-14 is 5730 years.)\r
\n" ); document.write( "\n" ); document.write( "I got:
\n" ); document.write( "m(t) = m0e^-(ln2/n)t
\n" ); document.write( "0.59 = 1e^-(ln2/5730)t
\n" ); document.write( "ln(0.59) = -(ln2/5730)t
\n" ); document.write( "t = 5730(ln0.59)/ln2 = 4,362 years ago\r
\n" ); document.write( "\n" ); document.write( "Does this seem right?\r
\n" ); document.write( "\n" ); document.write( "Thanks for all your wonderful help!
\n" ); document.write( "

Algebra.Com's Answer #31908 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Your formula certainly works and your answer is essentially
\n" ); document.write( "correct. I use a different formula for half-life problems.
\n" ); document.write( "For what it is worth I get:\r
\n" ); document.write( "\n" ); document.write( "0.59A = A(1/2)^(t/5730)
\n" ); document.write( "0.59 = (1/2)^(t/5730)
\n" ); document.write( "ln0.59 = (t/5730)(ln0.5)
\n" ); document.write( "t=5730[(ln0.59/ln0.5]
\n" ); document.write( "t= 4361.75 yrs.\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
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