document.write( "Question 465551: Solve using any method. (x/2) + (y/3) = 2/3 and (x/5) + (5y/2) = 1/4
\n" ); document.write( "I cannot figure out how to do this problem I have been working on it for an hour and have not figured it out please help.
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Algebra.Com's Answer #319062 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi
\n" ); document.write( "Solve using any method.
\n" ); document.write( "(x/2) + (y/3) = 2/3 |multiplying thru by 6
\n" ); document.write( "(x/5) + (5y/2) = 1/4 |multiplying thru by 20\r
\n" ); document.write( "\n" ); document.write( "(3x) + (2y) = 4
\n" ); document.write( "(4x) + (50y) = 5\r
\n" ); document.write( "\n" ); document.write( "(-4x) + (-8/3y) = 4*(-4/3) = -16/3 |Multiplying 1st EQ by -4/3
\n" ); document.write( "(4x) + (50y) = 5
\n" ); document.write( " 142/3 y= -1/3
\n" ); document.write( " y = -1/142 and x = 190/142 \n" ); document.write( "
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