document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=465596>Question 465596</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of  the measures of two acute <s is 110. The supplement of the smaller , is 15 times the complement of the larger <. fin the measures of the two acute <s. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #319034 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=319034\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of  the measures of two acute <s is 110. The supplement of the smaller , is 15 times the complement of the larger <. find the measures of the two acute <s.<BR>\n" );
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document.write( "Let one of the angle be \"x\".<BR>\n" );
document.write( "Then the other is \"110-x\".<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "180-x = 15[90-(110-x)]<BR>\n" );
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document.write( "180-x = 15[-20+x]<BR>\n" );
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document.write( "180-x = -300+15x<BR>\n" );
document.write( "16x = 480<BR>\n" );
document.write( "x = 30 degrees (one of the angles)<BR>\n" );
document.write( "110-30 = 80 degrees (the other angle)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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