document.write( "Question 465532: log2x+1/2log2(x+2)=2
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Algebra.Com's Answer #319028 by lwsshak3(11628)\"\" \"About 
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log2x+1/2log2(x+2)=2
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\n" ); document.write( "log2x+1/2log2(x+2)=2
\n" ); document.write( "rewrite as single log
\n" ); document.write( "log2[(x)(x+2)^1/2]=2
\n" ); document.write( "convert to exponential form: (base(2) raised to log of number(2)=number[(x)(x+2)^1/2]
\n" ); document.write( "2^2=(x)(x+2)^1/2=4
\n" ); document.write( "square both sides
\n" ); document.write( "x^2(x+2)=16
\n" ); document.write( "x^3+2x^2-16=0
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\n" ); document.write( "Don't know how to solve this equation algebriacally, but my graphing calculator shows there is one real root, x=2
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