document.write( "Question 465504: Could you please help me by providing a step-by-step answer to the following equation:
\n" ); document.write( "A museum offers excursions at $12.00 per ticket if 100 or fewer tickets are purchased. For each ticket over 100, the price is reduced by 10 cents. How many tickets will lead to a maximum income? (Solve using a quadratic formula.)\r
\n" ); document.write( "\n" ); document.write( "I'm familiar with the quadratic formula and how to use it, but I'm not quite sure how to approach this particular word problem.
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Algebra.Com's Answer #319000 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
Let x = number of tickets over 100.
\n" ); document.write( "==> price of ticket is 12 - 0.10x
\n" ); document.write( "==> number of tickets is 100 + x\r
\n" ); document.write( "\n" ); document.write( "==> Income, or revenue, is \"%28100+%2B+x%29%2812+-+0.10x%29+=+1200+%2B+2x+-+0.10x%5E2\". Since the the coefficient of \"x%5E2\" is negative (-0.10), there is an absolute maximum (parabola faces downward). The x-value that gives the maximum income is \"-b%2F%282a%29+=+-2%2F%282%2A-0.10%29+=+2%2F0.20+=+10\". Hence 100 + 10 = 110 tickets must be sold to get maximum income.
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