document.write( "Question 465502: I need to solve the following:\r
\n" ); document.write( "\n" ); document.write( "\"+e%5Ex+\"-\"+1%2Fe%5Ex+\"=2\r
\n" ); document.write( "\n" ); document.write( "*I had to write this differently because of the formula plotting system (the second part is really e to the -x instead of 1/e^x).\r
\n" ); document.write( "\n" ); document.write( "So I believe from here you subtract 2 from both sides and end up with everything equal to zero, and then you would let u=\"+e%5Ex+\", so that you have u-(1/u)-2=0. Then I get confused as to how to solve this by using the quadratic formula, because I don't know what b=? . That is really all I am confused on, assuming I'm going about this the right way in the first place.\r
\n" ); document.write( "\n" ); document.write( "I hope I've explained that well. Thanks!\r
\n" ); document.write( "\n" ); document.write( "Jessica
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Algebra.Com's Answer #318993 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
\"+e%5Ex+\"-\"+1%2Fe%5Ex+\"=2
\n" ); document.write( "Multiply thru by e^x
\n" ); document.write( "\"e%5E%282x%29+-+1+=+2e%5Ex\"
\n" ); document.write( "\"e%5E%282x%29+-+2e%5Ex+-+1+=+0\"
\n" ); document.write( "Sub u for e^x
\n" ); document.write( "\"u%5E2+-+2u+-+1+=+0\"
\n" ); document.write( "u = 1 +/- sqrt(2)
\n" ); document.write( "x = ln(1 +/- sqrt(2))
\n" ); document.write( "-------------
\n" ); document.write( "PS hyp cos(x) = \"%28e%5Ex+%2B+e%5E%28-x%29%29%2F2%29\"
\n" ); document.write( "hyp sin(x) = \"%28e%5Ex+-+e%5E%28-x%29%29%2F2%29\"
\n" ); document.write( "
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