document.write( "Question 48222This question is from textbook College Algebra
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document.write( ": A biologist has two brine solutions, one containing 5% salt and another containing 20% salt. How many milliliters of each solution should he mix to obtain 1 L of a solution that contains 14% salt?\r
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document.write( "Thank you so much for all your help!! \n" );
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Algebra.Com's Answer #31899 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A biologist has two brine solutions, one containing 5% salt and another containing 20% salt. How many milliliters of each solution should he mix to obtain 1 L of a solution that contains 14% salt? \n" ); document.write( "----------------------------------------- \n" ); document.write( "5% solution DATA: \n" ); document.write( "amount = x liters ; amount of salt = .05x liters \n" ); document.write( "----------------------------------------- \n" ); document.write( "20% solution DATA: \n" ); document.write( "amount = 1-x liters ; amount of salt = 0.20(1-x) = 0.20 -0.20x liters \n" ); document.write( "------------------------------------------- \n" ); document.write( "14% solution DATA: \n" ); document.write( "amount = 1 liter ; amount of salt = 0.14(1) = 0.14 liter\r \n" ); document.write( "\n" ); document.write( "EQUATION: \n" ); document.write( "salt + salt = salt \n" ); document.write( "0.05x + 0.20-0.20x = 0.14 \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "5x + 20 - 20x = 14 \n" ); document.write( "-15x=-6 \n" ); document.write( "x=2/5 = 0.4 liter (amount of 5% solution to be mixed) \n" ); document.write( "1-x=0.6 liter (amount of 20% solution to be mixed)\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |