document.write( "Question 465367: give the logarithms of the following.\r
\n" ); document.write( "\n" ); document.write( "1. log 1000\r
\n" ); document.write( "\n" ); document.write( "2. log 3.20\r
\n" ); document.write( "\n" ); document.write( "3. log(1000)^1/2 <--- thats the whole exponent the 1/2
\n" ); document.write( "

Algebra.Com's Answer #318950 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
give the logarithms of the following.\r
\n" ); document.write( "\n" ); document.write( "1. log 1000
\n" ); document.write( "1000 = 10^3 --> log(1000) = 3
\n" ); document.write( "----------------
\n" ); document.write( "2. log 3.20 =~ 0.50515
\n" ); document.write( "------------------
\n" ); document.write( "3. log(1000)^1/2
\n" ); document.write( "= 1/2 log(1000) = 3/2 or 1.5
\n" ); document.write( "
\n" );