document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=465332>Question 465332</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me to solve this problem. A manufacturer's marginal-cost function is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=dc%2Fdq=0.2q%2B8 ALIGN=MIDDLE  ALT=\"dc%2Fdq=0.2q%2B8\"   DISABLED_style= \"max-width:90%; height:auto;\" >. If c is in dollars, determine the cost involved to increase production from 65 to 75 units. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #318918 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=318918\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The increase from 65 to 75 units can be modeled by the integral\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \int_{65}^{75} (0.2q + 8)\, dq\">\r<BR>\n" );
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document.write( "because the marginal cost represents how much more it costs to increase one unit (or an arbitrarily small number of units) and the integral \"accumulates\" this cost.\r<BR>\n" );
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document.write( "Integrating, we get\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \int_{65}^{75} (0.2q + 8) = 0.1q^2 + 8q = (0.1(75)^2 + 8(75)) - (0.1(65)^2 + 8(65)) = 220\"> </SPAN>\n" );
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