document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=464583>Question 464583</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me verify using identities:\r<BR>\n" );
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document.write( "((sec theta - tan theta)^2 +1)/(sec theta csc theta -tan theta csc theta)=2tan theta </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #318907 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=318907\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ((sec theta - tan theta)^2 +1)/(sec theta csc theta -tan theta csc theta)=2tan theta<BR>\n" );
document.write( "...<BR>\n" );
document.write( "[(sec-tan)^2+1]/(sec*csc-tan*csc)=2tan<BR>\n" );
document.write( "[sec^2-2sec*tan+tan^2+1]/[(1/cos)(1/sin)-(sin/cos)(1/sin)]<BR>\n" );
document.write( "identity: tan^2+1=sec^2<BR>\n" );
document.write( "[2sec^2-2(1/cos)(sin/cos)]/[1/(cos*sin)-sin/(cos*sin)]<BR>\n" );
document.write( "(2/cos^2-2sin/cos^2)/(1-sin)/(cos*sin)<BR>\n" );
document.write( "(2(1-sin)/cos^2)/(1-sin)/(cos*sin)<BR>\n" );
document.write( "(1-sin) cancels out<BR>\n" );
document.write( "2(cos*sin)/cos^2=2sin/cos=2tan<BR>\n" );
document.write( "Identity verified: left side=right side </SPAN>\n" );
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