document.write( "Question 465377: If 3x^2-2x+7=0, then (x-1/3)^2=?? \n" ); document.write( "
Algebra.Com's Answer #318904 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! If 3x^2-2x+7=0 \n" ); document.write( "Solve for \"x\": \n" ); document.write( "x = [2+-sqrt(4-4*3*7)]/6 \n" ); document.write( "--- \n" ); document.write( "x = [2 +- sqrt(80)]/6 \n" ); document.write( "--- \n" ); document.write( "x = [2 +- 4sqrt(3)]/6 \n" ); document.write( "---- \n" ); document.write( "x = [1 + 2sqrt(3)]/3 or x = [1 - 2sqrt(3)]/3 \n" ); document.write( "================================================= \n" ); document.write( " then (x-1/3)^2=?? \n" ); document.write( "--- \n" ); document.write( "If x = [1+2sqrt(3)]/3 \n" ); document.write( "then (x-(1/3)^2 \n" ); document.write( "= [[1+2sqrt(3)]/3 - (1/3)]^2 \n" ); document.write( "= [2sqrt(3)/3]^2 \n" ); document.write( "= 4/3 \n" ); document.write( "---- \n" ); document.write( "If x = [1-2sqrt(3)]/3 \n" ); document.write( "then (x-(1/3)^2 = 4/3 \n" ); document.write( "========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |