document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=48191>Question 48191</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need a little help with this one please:\r<BR>\n" );
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document.write( "Maximizing profit. The total profit (in dollars) for sales of “x” rowing machines is given by P(x) = -0.2x² + 300x – 200. \r<BR>\n" );
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document.write( "What is the profit if 500 are sold? \r<BR>\n" );
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document.write( "For what value of “x” will the profit be at a maximum?\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31888 by </B><A HREF=/tutors/aboutme.mpl?userid=jake_6233><B>jake_6233(74)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jake_6233><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31888\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(x) = -0.2x² + 300x – 200 Realize that x=500 and then substitue it in to the function so<BR>\n" );
document.write( " P(500)=-0.2(500)² + 300(500) – 200\r<BR>\n" );
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document.write( "I'll let you do the rest as I am without my calculator at the moment.  Please let me know if you need more help with this problem  </SPAN>\n" );
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