document.write( "Question 465346: An urn contains 8 balls identical in every way except color. There are 4 blue balls, 3 red balls, and 1 yellow ball.\r
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\n" ); document.write( "\n" ); document.write( "b) You draw 2 balls from the urn but do not replace the first before drawing the second. What is the probability that both balls are red?\r
\n" ); document.write( "\n" ); document.write( "c) Explain the difference (if any) in the two problems. \n" ); document.write( "

Algebra.Com's Answer #318872 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "8 balls: 4blue,3red,1yellow
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document.write( "drawing 2 balls:
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document.write( "with replacement: p(both red) = 3/8*3*8 = 9/64 = .1406
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document.write( "w/o replacement: P(both red) = 3/8*2/7 = 6/56 = 3/28 = .1071
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document.write( "with replacement, there is a greater chance the 2nd will be red. \n" );
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