document.write( "Question 48179This question is from textbook Finite math
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document.write( ": A box contains 4 red and 5 green balls. Three balls are drawn. The probability 2 red and 1 green are drawn are drawn is.\r
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document.write( "1, 1/3
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document.write( "2, 4/9
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document.write( "c. 5/14
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document.write( "d. 3/5 My answer is 4/9, 4/9=.44 amd 5/9=.55 is this right. Thanks for any help given. \n" );
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Algebra.Com's Answer #31885 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A box contains 4 red and 5 green balls. Three balls are drawn. The probability 2 red and 1 green are drawn are drawn is.\r \n" ); document.write( "\n" ); document.write( "Draw the 2 red in 4C2 = 6 ways \n" ); document.write( "Draw the 1 green in 5C1=5 ways \n" ); document.write( "Draw 3 of any kind 9C3 = 9*8*7/1*2*3 = 84\r \n" ); document.write( "\n" ); document.write( "Prob (2R and 1G)= #of ways to suceed / # of possible outcomes \n" ); document.write( "= 6*5/84 = 15/42=5/14\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |