document.write( "Question 48164This question is from textbook College Algebra
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document.write( ": Find all solutions of the system of equations\r
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document.write( "xy=24
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document.write( "2x^2-y^2+4 = 0\r
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document.write( "Thank you so very much! \n" );
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Algebra.Com's Answer #31882 by deepblue(1)![]() ![]() ![]() You can put this solution on YOUR website! HI freind,\r \n" ); document.write( "\n" ); document.write( "these equations generally lead to quadratic equations\r \n" ); document.write( "\n" ); document.write( "given xy=24 and 2x^2-y^2+4=0\r \n" ); document.write( "\n" ); document.write( "in the second eqn substitute y=24/x \n" ); document.write( "u get,\r \n" ); document.write( "\n" ); document.write( "2x^2-(24/x)^2+4=0\r \n" ); document.write( "\n" ); document.write( "simplifying we get 2x^4+4x^2-(24)^2=0\r \n" ); document.write( "\n" ); document.write( "now assume x^2=p and substitute in teh above eqn we get\r \n" ); document.write( "\n" ); document.write( "2p^2+4p-(24)^2=0\r \n" ); document.write( "\n" ); document.write( "which is a normal quadratic equation\r \n" ); document.write( "\n" ); document.write( "whose solutions are \n" ); document.write( "p=16 and p=-18\r \n" ); document.write( "\n" ); document.write( "case 1:x^2=p=16\r \n" ); document.write( "\n" ); document.write( "=> x=+sqrt(p) or - sqrt(p) =+4 or -4\r \n" ); document.write( "\n" ); document.write( "case 2:when x^2=p=-18\r \n" ); document.write( "\n" ); document.write( "x=- sqrt(-18)or + sqrt(-18) \n" ); document.write( " =-4.24i or 4.24i (we know sqrrt(-1)=i)\r \n" ); document.write( "\n" ); document.write( "hence we have four slutions\r \n" ); document.write( "\n" ); document.write( "two are real and otehr two are complex!\r \n" ); document.write( "\n" ); document.write( "now having got x , y=24/x\r \n" ); document.write( "\n" ); document.write( "so values of y follow (but take care! x=0 can never be a solution! if x=0 then y=24/x becomes 24/0....which is undefined!)\r \n" ); document.write( "\n" ); document.write( "hope i solved ur question!\r \n" ); document.write( "\n" ); document.write( "take care \n" ); document.write( " |