document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=48105>Question 48105</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three years ago, Rica was thrice old as Dandy. Three years hence, she will be twice as old. Find their present ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31881 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31881\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x represent Rica's age and let y represent Dandy's age<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "\"Three years ago, Rica was thrice old as Dandy\"<BR>\n" );
document.write( "-->3(y-3)=x-3, x=3y-6 (SUBSITUTION)\r<BR>\n" );
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document.write( "EQUATION 2:<BR>\n" );
document.write( "\"Three years hence, she will be twice as old. Find their present ages\"<BR>\n" );
document.write( "-->2(y+3)=x+3<BR>\n" );
document.write( "2y+6=x+3<BR>\n" );
document.write( "Subsitute for x:<BR>\n" );
document.write( "2y+6=3y-6+3<BR>\n" );
document.write( "2y+6=3y-3<BR>\n" );
document.write( "y=9<BR>\n" );
document.write( "x=3(9)-6, x=21<BR>\n" );
document.write( "Hence, Rica is 21 years old and Dandy is 9 years old.<BR>\n" );
document.write( "Paul.<BR>\n" );
document.write( " </SPAN>\n" );
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