document.write( "Question 465170: Sir / Ma'am .. i don't know how to check this using substitution method .. it only needs to be checked.. here the problem :\r
\n" ); document.write( "\n" ); document.write( "4x+y+1 over 2 =14
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Algebra.Com's Answer #318757 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"4x%2By%2B1%2F2+=14\"\r
\n" ); document.write( "\n" ); document.write( "to check this using substitution method, you need \"x\" and \"y\" values ...plug them in your equation and if the left side of equation is equal to the right side \"x\" and \"y\" values are solutions.\r
\n" ); document.write( "\n" ); document.write( "I will take for \"x=2\" and \"y=5\" and check if these values are solutions:\r
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\n" ); document.write( "\n" ); document.write( "using substitution method we have \"4%2A2%2B5%2B1%2F2+=14\"\r
\n" ); document.write( "\n" ); document.write( "\"8%2B5%2B1%2F2+=14\"\r
\n" ); document.write( "\n" ); document.write( "\"13%281%2F2%29+=14\"\r
\n" ); document.write( "\n" ); document.write( "\"13.5+=14\".......... the left side of equation is NOT equal to the right side \"x\" and \"y\" values are NOT solutions.\r
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\n" ); document.write( "\n" ); document.write( "now, I will take for \"x=2\" and \"y=5.5\" and check if these values are solutions:\r
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\n" ); document.write( "\n" ); document.write( "using substitution method we have \"4%2A2%2B5.5%2B1%2F2+=14\"\r
\n" ); document.write( "\n" ); document.write( "\"8%2B5.5%2B1%2F2+=14\"\r
\n" ); document.write( "\n" ); document.write( "\"13.5+%2B0.5+=14\"\r
\n" ); document.write( "\n" ); document.write( "\"14+=14\".......... the left side of equation IS equal to the right side \"x\" and \"y\" values ARE solutions.\r
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