document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=465044>Question 465044</A>: <I><SPAN STYLE=\"word-break: break-all;\"> dolores is on a bridge that is 5o ft above a lake. she sees a boat at a 30 degree angle of depression. what is doloress horizontal distance from the boat? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #318601 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=318601\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "30-60-90 right triangle.  Short leg is the vertical distance from Dolores' height of eye to the water below.  Sides are in proportion <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \frac{1}{2}:\frac{\sqrt{3}}{2}:1\">.  So if the short leg is 50 feet, then the hypotenuse is 100 feet and the long leg (the desired distance) is <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large 50\sqrt{3}\">\r<BR>\n" );
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document.write( "And next time, show Dolores a little respect -- capitalize her name.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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