document.write( "Question 48149: Solve the equation for the indicated variable. (Leave ± in your answer, when appropriate.)\r
\n" ); document.write( "\n" ); document.write( "\"rm=t%5E2-mt\" for t \n" ); document.write( "
Algebra.Com's Answer #31855 by Earlsdon(6294)\"\" \"About 
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Solve fot t:\r
\n" ); document.write( "\n" ); document.write( "\"rm+=+t%5E2-mt\" You can use the quadratic formula or \"complete the square\" to solve this: Let's use the quadratic formula: \"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\"
\n" ); document.write( "First put your equation into the standard form:\r
\n" ); document.write( "\n" ); document.write( "\"t%5E2-mt-mr+=+0\" Here, a = 1, b = -m, and c = -rm\r
\n" ); document.write( "\n" ); document.write( "\"t+=+%28-%28-m%29%2B-sqrt%28%28-m%29%5E2-4%281%29%28-rm%29%29%29%2F2%281%29\" It looks complicated but we can simplify it a bit.\r
\n" ); document.write( "\n" ); document.write( "\"t=%28m%2B-sqrt%28m%5E2%2B4rm%29%29%2F2\" or, if you like:
\n" ); document.write( "\"t+=+%28m%2F2%29%2B-sqrt%28m%5E2%2B4rm%29%2F2\" \n" ); document.write( "
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