document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=464996>Question 464996</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve using the substitution method 0.3x + 0.2y = 5, 0.5x + 0.4y = 11 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #318548 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=318548\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .3x+.2y=5<BR>\n" );
document.write( "3x+2y=50<BR>\n" );
document.write( "6x+4y=100<BR>\n" );
document.write( "4y=100-6x;<BR>\n" );
document.write( ".5x+.4y=11<BR>\n" );
document.write( "5x+4y=110<BR>\n" );
document.write( "4y=110-5x<BR>\n" );
document.write( "110-5x=100-6x<BR>\n" );
document.write( "x=-10<BR>\n" );
document.write( "2y=80<BR>\n" );
document.write( "y=40.. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );