document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=48142>Question 48142</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0073016020/algebrahomeworkh>Beginning Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> section 6.1 <BR>\n" );
document.write( "Please help: I do not get this\r<BR>\n" );
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document.write( "Complete the ordered pairs so that each is a solution for the qiven equation.\r<BR>\n" );
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document.write( "3x + 4y=12 (0,  ), (  , 3/4), (  ,0),(8/3,  ) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31852 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31852\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x+4y = 12\r<BR>\n" );
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document.write( "First ordered pair (x, y) is (0, y) To find the value of y, substitute x = 0 into your equation and solve for y.\r<BR>\n" );
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document.write( "3(0)+4y = 12<BR>\n" );
document.write( "0+4y = 12 Divide both sides of the equation by 4.<BR>\n" );
document.write( "y = 12/4 = 3\r<BR>\n" );
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document.write( "The first ordered pair is: (0, 3)\r<BR>\n" );
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document.write( "One more:\r<BR>\n" );
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document.write( "The second ordered pair (x, y) is (x, 3/4). To find the value of x, substitute y = 3/4 into your equation and solve for x.\r<BR>\n" );
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document.write( "3x+4(3/4) = 12 Simplify.<BR>\n" );
document.write( "3x+3 = 12 Subtract 3 from both sides.<BR>\n" );
document.write( "3x = 9 Now divide both sides by 3.<BR>\n" );
document.write( "x = 3\r<BR>\n" );
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document.write( "The second ordered pair (x, y) is (3, 3/4)\r<BR>\n" );
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document.write( "Use the same technique to find the other ordered pairs<BR>\n" );
document.write( " </SPAN>\n" );
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