document.write( "Question 464963: solve for x: 6x^2=23x-15 \n" ); document.write( "
Algebra.Com's Answer #318514 by Gogonati(855)\"\" \"About 
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First we set the equation \"6x%5E2=23x-15\" equal to zero:\r
\n" ); document.write( "\n" ); document.write( "\"6x%5E2-23x%2B15=0\". To solve the equation we use the quadratic formula:\r
\n" ); document.write( "\n" ); document.write( "\"x=%2823%2B-sqrt%2823%5E2-4%2A6%2A15%29%29%2F%282%2A6%29=+%2823%2B-sqrt%28169%29%29%2F12\". As you see we have\r
\n" ); document.write( "\n" ); document.write( "two solutions:\"x=%2823%2B13%29%2F12=3\" and \"x=%2823-13%29%2F12=10%2F12=5%2F6\".
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