document.write( "Question 464911: solve for x: 2^(2x) + 2^(x+2) - 12 = 0, I believe logarithms are needed. \n" ); document.write( "
Algebra.Com's Answer #318483 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
x = 1
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\n" ); document.write( "The hard way:
\n" ); document.write( "\"2%5E%282x%29+%2B+2%5E%28x%2B2%29+-+12+=+0\"
\n" ); document.write( "\"2%5Ex%2A%282%5Ex+%2B+4%29+-+12+=+0\"
\n" ); document.write( "\"2%5E2x+%2B+4%2A2%5Ex+-+12+=+0\"
\n" ); document.write( "Sub y for 2^2
\n" ); document.write( "\"y%5E2+%2B+4y+-+12+=+0\"
\n" ); document.write( "(y+6)*(y-2) = 0
\n" ); document.write( "y = 2^x = -6, 2
\n" ); document.write( "Ignore the -6
\n" ); document.write( "2^x = 2
\n" ); document.write( "x = 1
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