document.write( "Question 464907: I had a 91 average in a class I was taking.... our final was 2 parts and worth 35% of our grade, I scored a 83 on the first half, what would I have had to score on the 2nd half to receive a 79.5 for a final grade? \n" ); document.write( "
Algebra.Com's Answer #318478 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! 91x.65=59.15 \n" ); document.write( "79.5-59.15=20.35 \n" ); document.write( "83x.35/2=14.525 \n" ); document.write( "20.35-14.525=5.825 \n" ); document.write( ".35/2=.175 \n" ); document.write( "m(.175)=5.825 \n" ); document.write( "m=5.825/.175=33.286 \n" ); document.write( "You need a score of 33.286 on the second half of the test to get a 79.5 average in the class. \n" ); document.write( " |