document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=464874>Question 464874</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary if their sum equals 180. The larger angle is five degrees more than twice the smaller angle. If x represents the smaller angle, find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #318468 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=318468\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = smaller angle<BR>\n" );
document.write( "180 - x = larger angle\r<BR>\n" );
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document.write( "180 - x = 2x + 5 {larger angle is 5 more than twice the smaller}<BR>\n" );
document.write( "180 = 3x + 5 {added x to both sides}<BR>\n" );
document.write( "175 = 3x {subtracted 5 from both sides}<BR>\n" );
document.write( "x = 58 1/3° {divided both sides by 3}<BR>\n" );
document.write( "180 - x = 121 2/3° {substituted 58 1/3, in for x, into 180 - x}\r<BR>\n" );
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document.write( "smaller angle is 58  1/3° <BR>\n" );
document.write( "larger angle is 121  2/3° <BR>\n" );
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